java

findFactorsNumber()

Parameters: int number

Input is a single integer for which the factors are to be calculated

Returns: A List of Integers which are the factors of the input

This function iterates through a given number. It checks if the number is divisible by the iteration index. If true, it adds the index to the list of factors.

looping
conditionals
arithmetic operations
array manipulation
Medium dificulty

Writing a Java program to find factors of a number

Hello there, fellow programmer. In this guide you'll embark on an intriguing venture because we're about to take an adventure into the world of functional programming in Java. We're going to grasp how to write up a function to compute the factors of a number. Absorbing this function can undeniably expand your arsenal of problem-solving tools. Enjoy the journey!

Step 1: Understand the Problem

The first step in solving this problem is to understand what we are trying to achieve. We need to find all the factors of a given number. In other words, we are attempting to find all numbers which divide evenly into our input number, without leaving a remainder. This is a common task in programming and mathematics, and can be solved using a simple for loop in java.

Step 2: Initialize an ArrayList

To store the factors of the number, we will use an ArrayList. An ArrayList in Java is like an array but it provides us with more flexibility in terms of storage.

ArrayList<Integer> factors = new ArrayList<Integer>();

Step 3: Implement the Logic

Now, we will loop through all numbers from 1 to the given number, and check if the number is a factor. If a number divides evenly into our input, we add it to our factors list.

for (int i=1; i<=num; i++){
   if (num % i == 0){
      factors.add(i);
   }
}

Step 4: Create a Method

To make our implementation neat and reusable, it's ideal to put our code in a separate method named findFactors. The method returns an ArrayList and takes an integer as input.

public ArrayList<Integer> findFactors(int num){
   ArrayList<Integer> factors = new ArrayList<Integer>();
   for (int i=1; i<=num; i++){
      if (num % i == 0){
         factors.add(i);
      }
   }
   return factors;
}

Conclusion

With these steps, we should be able to find all the factors of a given number. The full implementation in Java is as follows:

import java.util.ArrayList;

public class Main{

   public static void main(String args[]){
      ArrayList<Integer> factors = findFactors(12);
      for(int factor: factors){
         System.out.print(factor + " ");
      }
   }

   public static ArrayList<Integer> findFactors(int num){
      ArrayList<Integer> factors = new ArrayList<Integer>();
      for (int i=1; i<=num; i++){
         if (num % i == 0){
            factors.add(i);
         }
      }
      return factors;
   }
}

This script will print all the factors of the number 12. You can replace 12 with any number you want to find the factors of.

Learn function in:

Factorization

Factorization is dividing a number into its smallest integral divisors.

Learn more

Mathematical principle

Finding factors relies on division and the modulus operation. In this function, the number is divided by every integer starting from 1 up to the number itself. If the remainder (`num % i`) is equal to 0, it means that `i` is a factor of `num` because it divides exactly into `num`.

Learn more