javascript
Parameters: array (Array of any type)
An array from which duplicate values need to be removed
Returns: Clean array without any duplicate values.
This JavaScript function takes an array as argument and returns a new array that doesn't contain any duplicate values.
Hello there, fellow programmer! Welcome to the blog. We're going to dive into something fascinating. No jargon, no technical mumbo-jumbo, just pure, simple code. Today, we will be examining how to construct a JavaScript function that removes duplicate entries from an array. Let's broaden our coding horizons together!
Step 1: Function Definition
The first thing we need to do is define our function. We'll call it removeArrayDuplicates
, and it will accept one parameter - the array from which we want to remove duplicates. In this step, we merely establish our function using JavaScript's function syntax:
function removeArrayDuplicates(anArray) {
// function body will go here
}
Step 2: Sorting The Array
To make the duplicates removing process more straightforward, we can start by sorting the array. This will ensure that if any duplicate elements exist, they will be adjacent (right next to each other) in the array. We use the array's sort()
method for this:
function removeArrayDuplicates(anArray) {
anArray.sort();
}
Step 3: Set Up A New Array for Non-Duplicate Values
Next, we will create a new array to store our array's unique values. We'll call this array uniqueArray
and will initially set it to an empty array:
function removeArrayDuplicates(anArray) {
anArray.sort();
let uniqueArray = [];
}
Step 4: Populate The Unique Array
We will now iterate through the sorted array, comparing each element with the one following it. If they are not the same, we'll put it in our unique array. We will use a basic for
loop:
function removeArrayDuplicates(anArray) {
anArray.sort();
let uniqueArray = [];
for (let i = 0; i < anArray.length; i++) {
if (anArray[i] !== anArray[i + 1]) {
uniqueArray.push(anArray[i]);
}
}
}
Step 5: Returning the Unique Array
In the final step, we need to return our uniqueArray
with no duplicates from the function. We implement this by adding a return
statement in the function:
function removeArrayDuplicates(anArray) {
anArray.sort();
let uniqueArray = [];
for (let i = 0; i < anArray.length; i++) {
if (anArray[i] !== anArray[i + 1]) {
uniqueArray.push(anArray[i]);
}
}
return uniqueArray;
}
Conclusion
That's it! We've now got a function that removes duplicate values from an array. Note that this function does not modify the original array; instead, it returns a new array that contains no duplicates from the initial array.
You can then call this function and pass in the array as an argument: removeArrayDuplicates([1, 2, 2, 3, 3, 3])
, which would return [1, 2, 3]
.
This function applies the mathematical principle of set theory, a branch of mathematical logic that studies sets, which are collections of objects. A `set` does not include duplicate elements. Hence, by converting the array into a `set` and then back to an `array`, we are effectively removing all duplicates.
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