java

findPalindromeNumbersInRange()

Parameters: int start, int end

Start and end of range for finding palindromes

Returns: List of integer palindrome numbers in given range

This Java function, findPalindromeNumbersInRange, receives a start and end number and returns the palindrome numbers within that range.

Loop concept
Conditional Statements
Functions
Variables
Data Types
Medium dificulty

Writing Java Function to Identify Palindrome Numbers in a Given Range

Hello, fellow programmer! Today, we'll be diving into the fascinating concept of creating a function specifically designed to identify palindrome numbers within any given range. Using Java as our primary programming language, we'll be exploring step-by-step the various methods and processes involved in this task. Despite its complexity, we'll provide a comprehensive approach to solving this problem - equipping you with the knowledge to apply this to your future programming endeavors. So, buckle up and get ready to code!

Step 1:

The first step is to build a base function that checks if a given number is a palindrome. This will be done by converting the number into a string and then comparing this string with its reverse.

public static boolean isPalindrome(int number) {
    String numberAsString = String.valueOf(number);
    return numberAsString.equals(new StringBuilder(numberAsString).reverse().toString());
}

Step 2:

The next step is to use the isPalindrome function within a loop that goes through the specified range of numbers and adds any numbers that return true from the isPalindrome function to a list.

public static List<Integer> findPalindromesInRange(int start, int end) {
    List<Integer> palindromes = new ArrayList<Integer>();
    for (int i = start; i <= end; i++) {
        if (isPalindrome(i)) {
            palindromes.add(i);
        }
    }
    return palindromes;
}

Step 3:

Now that we have the base function ready, it's time to implement the rest of the functionality. The function findPalindromesInRange simply iterates from start to end inclusive and checks if the current number is a palindrome using the function isPalindrome(). If it is, the number is added to the list of palindrome numbers.

Step 4:

It's time to test our code! We can test it by using some known ranges that should contain palindromes. For example, testing the code with the range from 10 to 200 should return [11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191].

Step 5: The final step

In conclusion, our Java function successfully checks a given range for palindrome numbers. It does so by first checking if a number is a palindrome, before then iterating over the specified range and adding any palindrome numbers to a list. Here is our full code.

public class Main {

    public static boolean isPalindrome(int number) {
        String numberAsString = String.valueOf(number);
        return numberAsString.equals(new StringBuilder(numberAsString).reverse().toString());
    }

    public static List<Integer> findPalindromesInRange(int start, int end) {
        List<Integer> palindromes = new ArrayList<Integer>();
        for (int i = start; i <= end; i++) {
            if (isPalindrome(i)) {
                palindromes.add(i);
            }
        }
        return palindromes;
    }

    public static void main(String[] args) {
        System.out.println(findPalindromesInRange(10, 200));
    }
}

Learn function in:

Palindrome Numbers

Determine numbers that remain the same on reversal

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Mathematical principle

In mathematics, a palindrome number is a number that remains the same when its digits are reversed. Like 16461, it is read the same backwards. In this problem, we iterate through the given range of numbers. For each number, we reverse it and compare it to the original number. If they are equal, then it is a palindrome number. ```Example: given the range (100,200), the function will return [101, 111, 121, 131, 141, 151, 161, 171, 181, 191].```

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