java
Parameters: int num
An integer number to find its square
Returns: Square of the given number
The function takes an integer as input and returns the square of that integer. It's useful for mathematical and scientific computations.
Hello Programmer! Welcome to this blog post. We will keep it simple and professional, exploring a common fundamental in programming - finding the square of a number. In the following steps, we will walk through how to create a function in Java to achieve this task. Let's dive right in!
First and foremost, we need to prepare the basic structure of the function. In our Java function, we'll call it 'findSquare'. We'll declare our function 'findSquare', which takes one parameter, a number that we'll call 'num'. To simply declare the function without adding any logic to it, we refer the next code block.
public static int findSquare(int num) {
}
After laying out the basic structure of the function, we can now introduce the logic that does the actual work, which is squaring the number. We'll accomplish this in Java with the aid of the Math.pow() function. This function requires two parameters: the base number and the power to which it will be raised. In our case, both will be 'num'. Save this result in an integer variable named 'square'.
public static int findSquare(int num) {
int square = (int) Math.pow(num, 2);
}
Finally, we should return the computed result. In Java, this is done using the 'return' keyword followed by the variable we want to return.
public static int findSquare(int num) {
int square = (int) Math.pow(num, 2);
return square;
}
There you have it: a simple function in Java that will find the square of a given number. This is a simple but useful function, and it can be a basic component in larger systems or applications where mathematical calculations are required.
This function follows the mathematical principle of squaring a number. In mathematics, the square of a number 'n' is obtained when you multiply 'n' by itself. So `n*n` gives the square of 'n'.
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