java

find-sum-cubes-range()

Parameters: int start, int end

Start and end of the range are provided as integers

Returns: Returns the sum of cubes of numbers within the provided range

The find-sum-cubes-range function in Java is meant to find and return the sum of the cubes of numbers within a specific range. The function takes two arguments, the start and end of the range, and returns the cumulative sum of cubes.

variables
conditionals
loops
arithmetic operations
functions
return statements
Medium dificulty

Writing a Java Function to Calculate the Sum of Cubes in a Given Range

Hello, fellow programmer! This article is designed to guide you, step-by-step, through the process of programming a specific function in Java. The function we are focusing on today is commonly referred to as 'find-sum-cubes-range'. This function computes the sum of cubes over a certain range of numbers. Whether you're just familiarizing yourself with Java or honing your existing skills, this tutorial will undoubtedly prove beneficial.

Step 1: Understand the Problem

The function we want to create, find-sum-cubes-range, requires us to find the sum of the cubes of all the numbers within a specified range. For instance, the range 1-3 would have a sum of 1^3 + 2^3 + 3^3 = 36.

public class Main {
    public static void main(String[] args) {
        // Here we will implement our function
    }
}

Step 2: Begin the Function Implementation

We need to establish our function's parameters. We decide to take two integer inputs: start and end – these represent the beginning and end of our range.

public class Main {
    public static int findSumCubesRange(int start, int end) {
        // Here we will implement the logic
    }
}

Step 3: Loop Through the Range

Next, we implement a loop from the start to the end of the range and calculate the cube of each number, adding it to our sum variable.

public class Main {
    public static int findSumCubesRange(int start, int end) {
        int sum = 0;
        for (int i = start; i <= end; i++) {
            sum += i * i * i;
        }
        return sum;
    }
}

Step 4: Return the Sum

Finally, our function returns the sum. This is the total of all the cubes from the start to the end parameters.

public class Main {
    public static int findSumCubesRange(int start, int end) {
        int sum = 0;
        for (int i = start; i <= end; i++) {
            sum += i * i * i;
        }
        return sum;
    }

    public static void main(String[] args) {
        System.out.println(findSumCubesRange(1, 3)); // Outputs 36
    }
}

Step 5: Test the Function

The last step involves testing our function to ensure it correctly calculates the sum of cubes within the specified range. In the example above, the function correctly calculated the sum for the range 1 to 3. It's also advisable to test with different ranges.

Conclusion

So, creating a function in Java to compute the sum of cubes in a given range involves establishing a for loop to iterate through the range of integers, calculating the cube of each integer, and adding these cubes to a running total.

The completed function definition is as follows:

public class Main {
    public static int findSumCubesRange(int start, int end) {
        int sum = 0;
        for (int i = start; i <= end; i++) {
            sum += i * i * i;
        }
        return sum;
    }

    public static void main(String[] args) {
        System.out.println(findSumCubesRange(1, 3)); // Outputs 36
    }
}

Remember to always test your code with different inputs to ensure its robustness.

Learn function in:

Sum of cubes in a range

This function solves the problem of finding the sum of cubes of numbers within a certain range.

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Mathematical principle

This function uses the principle of arithmetic series which is a sequence of numbers in which each term after the first is obtained by adding a constant difference to the preceding term. In this case, the difference is the next cube. The formula used is `n(n+1)/2` squared, where `n` is the number till where you want to find the cubes.

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