javascript
Parameters: start(int), end(int)
start is the initial point, end is the final point of the range
Returns: Returns the sum of cubes of all numbers within the range
The findSumCubesRange function takes two integer parameters, representing a range (inclusive), and calculates the sum of cubes of all the numbers in the specified range.
Hello there, fellow programmer! Here is a cool way to calculate the sum of cubes within a range in javascript. Don't worry if you are a beginner or experienced as this guide will walk you through the steps of creating this function with a simple line-by-line explanation. This function can be useful in numerous mathematical calculations and performance optimizations. Happy coding!
The first step towards finding the sum of cubes in a given range is understanding what's being asked in the problem statement. In this case, the function findSumCubesRange
should take two parameters (let's call them start
and end
), and calculate the sum of the cubes of all the numbers in between these two parameters (including the start and end numbers).
Let's begin by setting up a skeleton function in JavaScript:
function findSumCubesRange(start, end) {
// detail implementation will be written here.
}
The next step is to validate the input by checking whether the start and end values are integers and the start is less than or equal to end. If one or both of these conditions are not met, then the function should return a message indicating an invalid input.
function findSumCubesRange(start, end) {
if (!Number.isInteger(start) || !Number.isInteger(end)) {
return "Invalid input. Please enter an integer number";
}
if (start > end) {
return "Invalid range. End must be greater than start";
}
}
We can initialize a variable sum
that will contain the total sum of the cubes. It should be set to zero before the calculations begin.
function findSumCubesRange(start, end) {
if (!Number.isInteger(start) || !Number.isInteger(end)) {
return "Invalid input. Please enter integer numbers";
}
if (start > end) {
return "Invalid range. End must be greater than start";
}
let sum = 0;
}
In the fourth step, let's loop through all the numbers from start
to end
(inclusive). For each of these numbers, we will calculate their cube (i.e., the number multiplied by itself twice) and add that cube to sum
.
function findSumCubesRange(start, end) {
if (!Number.isInteger(start) || !Number.isInteger(end)) {
return "Invalid input. Please enter integer numbers";
}
if (start > end) {
return "Invalid range. End must be greater than start";
}
let sum = 0;
for(let i = start; i <= end; i++) {
sum += Math.pow(i, 3);
}
}
Finally, after the end of the loop, the sum
variable will contain the total sum of the cubes of all the numbers in the passed range. Therefore, we should return this sum
from our function.
function findSumCubesRange(start, end) {
if (!Number.isInteger(start) || !Number.isInteger(end)) {
return "Invalid input. Please enter integer numbers";
}
if (start > end) {
return "Invalid range. End must be greater than start";
}
let sum = 0;
for(let i = start; i <= end; i++) {
sum += Math.pow(i, 3);
}
return sum;
}
In conclusion, the function findSumCubesRange
takes a range of numbers (from start
to end
) and returns the sum of the cubes of all the numbers within this range. This process involves validating the input, initializing a sum variable, computing the sum of cubes within a loop, and finally returning the total sum. By following these steps, you can understand and implement this function in JavaScript effectively.
This function utilizes the mathematical principle of summation (∑) and cubic (^3), where each integer in a range from `a` to `b` is raised to the power of 3 and these values are then summed. This can be mathematically depicted as ∑ for n=a to b (n^3).
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