java

findSumEvenNumbersInRange()

Parameters: int start, int end

The start and end points for the range of numbers to be calculated.

Returns: The function will return the sum of all even numbers in the specified range.

This Java function calculates the sum of all even numbers within a specified range. The range endpoints are inclusive and the function returns an integer sum.

variables
loops
conditional statements
arithmetic operations
Medium dificulty

How to Write a Java Function to Sum Even Numbers in a Range

Greetings, fellow programmer! In this blog post, we're going to explore a specific function in Java: find-sum-even-numbers-range. This function will enable us to find the sum of even numbers within a specified range. This is a great tool to add to your coding arsenal, as it's not only important for various logic-based problems, but it also helps deepen your understanding of loops and conditionals in Java. Stay tuned!

Step 1: Function Signature

The first step is to define the function signature. In java, it starts with the access modifier public, then the return type of the function which is int in our case followed by the function name and parameters. In this case, it needs two parameters, which are the start and end range for which we want to find the sum of even numbers.

public int findSumEvenNumbersRange(int start, int end){}

Step 2: Add loop

Inside this function, we need to iterate over range of numbers from start to end using a for loop.

public int findSumEvenNumbersRange(int start, int end){
  for(int i=start; i<=end; i++){}
}

Step 3: Add Condition

Next, we need to check if the number is even. We can do this using the modulus operator %. If a number i is even, i % 2 will be equal to 0.

public int findSumEvenNumbersRange(int start, int end){
  for(int i=start; i<=end; i++){
    if(i % 2 == 0){}
  }
}

Step 4: Add Sum Calculation

Inside the if statement we should add the conditional logic. For our case, we need to calculate the sum of the even numbers, therefore we will use the += operator to add the even number to our sum which is initially set to 0.

public int findSumEvenNumbersRange(int start, int end){
  int sum = 0;
  for(int i=start; i<=end; i++){
    if(i % 2 == 0){
      sum += i;
    }
  }
}

Step 5: Return the Result

Finally, after iterating over all the numbers and summing up the even numbers, we need to return the result. This is done by simply adding return sum; at the end of our function.

public int findSumEvenNumbersRange(int start, int end){
  int sum = 0;
  for(int i=start; i<=end; i++){
    if(i % 2 == 0){
      sum += i;
    }
  }
  return sum;
}

That's it, we have implemented the function to find the sum of even numbers in a given range in Java.

Learn function in:

Summation of Even Numbers within a Range

This calculates the total of all even numbers within a specified range.

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Mathematical principle

The function is based on the mathematical principle of Arithmetic Progressions (APs). An AP is a sequence of numbers in which the difference of any two successive members is a constant. In this case, the AP consists of even numbers. The sum of 'n' terms of an AP can be given by the formulae: `n/2 * (first term + last term)` or `n/2 * [2a + (n-1)d]` where 'n' is the number of terms, 'a' is the first term and 'd' is the common difference.

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