javascript
Parameters: int start, int end
Start and end of range, both integers
Returns: Sum of even numbers in range (integer)
The findSumEvenNumbersRange function in JavaScript is designed to compute the total sum of all even numbers that exist in a scope of numbers set by the user.
Welcome to this blog post, fellow programmer. We understand your insatiable thirst to crack codes and create something ingenious. In the following steps, we'll guide you in crafting a useful function in JavaScript called findSumEvenNumbersRange. This function will enable you to find the sum of even numbers in a specific range. Grab your favorite cup of coffee, roll up your sleeves, and let's dive into some engaging and stimulating coding!
Step 1: Understand the Problem and Initialize the Function
Before you start to code, it's crucial to understand what the question asks. In this case, we need to create a function, findSumEvenNumbersRange, that sums all of the even numbers within a certain range.
function findSumEvenNumbersRange(start, end) {}
Step 2: Initialize a Variable for the Sum
Inside the function, we'll create a variable to hold our sum. Let's call this variable 'sum'. Initially, sum would be zero as we haven't started adding any numbers yet.
function findSumEvenNumbersRange(start, end) {
var sum = 0;
}
Step 3: Use a Loop to Go Through Each Number in the Range
Next, we'll use a for loop to iterate (or "go through") each number between start and end, inclusive. We'll start at 'start', go until we reach 'end', and increase by 1 each time through the loop.
function findSumEvenNumbersRange(start, end) {
var sum = 0;
for(var i=start; i <= end; i++) {}
}
Step 4: Conditionally Add Even Numbers to Our Sum
We only want to sum up the even numbers. To check if a number is even, we can use the modulus operator (%). This operation gives us the remainder after division. If we divide a number by 2 and the remainder is 0, that means the number is evenly divisible by 2, and hence, it's even. If 'i' is even, we add it to our 'sum'.
function findSumEvenNumbersRange(start, end) {
var sum = 0;
for(var i=start; i <= end; i++) {
if(i % 2 === 0) {
sum += i;
}
}
}
Step 5: Return the Sum
Lastly, we need to return the final sum. This will be the output of our function.
function findSumEvenNumbersRange(start, end) {
var sum = 0;
for(var i=start; i <= end; i++) {
if(i % 2 === 0) {
sum += i;
}
}
return sum;
}
And voila! You've just created a JavaScript function that sums up all the even numbers in a given range. This function traverses the range once, making it an O(n) operation where n is the size of the range. Efficient and easy to read!
Remember: Programming is all about breaking down larger problems into smaller, more manageable parts. Take each step one at a time, and you'll have your problem solved in no time!
The function works on the mathematical principle of arithmetic progression where every next element is increased by '2' to ensure it's an even number. The sum of an arithmetic sequence is given by `(n/2)*(firstTerm + lastTerm)`, where `n` is the number of terms, and the `firstTerm` and `lastTerm` are the first and last terms of the sequence. Here, the sequence is of all even numbers between the given range.
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