java
Parameters: int num
num: The number to compute the sum of its digits
Returns: Integer representing the sum of all digits in num
The findSumOfDigits function takes a number as an input and computes the sum of its digits. It utilizes arithmetic operations embedded in a loop to calculate the result.
Hello Programmer! Welcome to our informative walk-through blog on utilizing Java programming to solve the interesting problem of finding the sum of digits in a given number. We believe learning through practical examples can be both fun and educative. Hence, we'll delve into code, dissect it and understand how it works. Let's get started!
The first step when solving any programming problem is understanding the problem. Our function, findSumOfDigits, will accept an integer as input. The function needs to return the sum of the digits in the input number.
For instance, if our function receives 123, it should output 6 as 1 + 2 + 3 = 6. Similarly, for input number 4567, the function should return 22 i.e. 4 + 5 + 6 + 7 = 22.
Now that we understand the problem we're attempting to solve, let's move to the implementation.
First, we must declare our function, which we're going to call findSumOfDigits
. This function will take an integer number
as its argument.
public class Main {
public static int findSumOfDigits(int number) {
}
}
In this step, we'll implement the logic to find the sum of the digits. We will use the modulus operator (%) to extract each digit from the number and add it to the sum. This process will continue until the number becomes 0.
public static int findSumOfDigits(int number) {
int sum = 0;
while (number != 0) {
sum = sum + number % 10;
number = number / 10;
}
return sum;
}
Let's now test our findSumOfDigits
function with a few test cases to ensure it's working as expected.
public static void main(String[] args) {
System.out.println(findSumOfDigits(123));
System.out.println(findSumOfDigits(4567));
}
In conclusion, we have successfully built our findSumOfDigits
function. It accepts an integer as input and returns the sum of its digits. Our function is successfully solving the problem as desired.
The function employs the basic mathematical principle of addition. The digits of the input number are separated using the modulus operation (`number % 10`) to get the remainder when divided by 10 (i.e. the last digit). This digit is then added to a running total. The number is then divided by 10 (`number / 10`) to remove the last digit. This cycle repeats until the number becomes 0.
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